10v^2-240v=0

Solution for 10v^2-240v=0 equation:

10v^2-240v=0

a = 10; b = -240; c = 0;
Δ = b2-4ac
Δ = -2402-4·10·0
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{57600}=240$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-240)-240}{2*10}=\frac{0}{20}
=0
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-240)+240}{2*10}=\frac{480}{20}
=24
$